Part -1:
1. The circuit diagram of FIGURE 1 is of a bell indicator circuit.
FIG. 1
(a) Convert this diagram into industrial ladder diagram format (retain all devices).
(b) (i) Convert the diagram of FIGURE 1 into a suitable PLC ladder diagram having the simplest form.
(ii) Provide I/O designation charts to show your choice of inputs and outputs.
(iii) State three benefits obtained by the PLC implementation.
2. The diagram of FIGURE 2 is an extract from an industrial control panel wiring diagram.
FIG. 2
(i) Convert the diagram into PLC format.
(ii) Identify all inputs and outputs by the use of I/O designation charts.
(iii) With respect to the operation of the circuit:
(a) explain the purpose of rung 1
(b) explain fully the condition of the circuit elements when indicator IND2 is illuminated
(c) If indicator IND3 is on, explain what will happen if P3 is operated.
3. Provide a block diagram of a PLC system which contains the following:
(i) (a) a CPU
(b) a system clock
(c) a power supply
(d) input and output interfaces
(e) a keyboard
(f) a display device
(g) necessary types of memory.
Describe very briefly the function and essential features of each block.
(ii) Use the diagram shown in FIGURE 3 to briefly explain the fetch/execute cycle of a microprocessor for the instruction 32 00 BC. The instruction is stored in memory locations 1661 to 1663. The op code means 'store the contents of the accumulator in memory address location'. The address given is in the reverse order. The contents of the accumulator are 78H. Indicate the contents of the PC, AS, registers, accumulator and address BC00 after the cycle is completed.
FIG. 3
4. The circuit of FIGURE 4 shows a 3-phase, star/delta motor starting circuit. The motor is initially connected in star (contactors C1 and C3 close to form a star with the three motor windings) and run up to speed, then the circuit is switched to run in delta (i.e. a triangular connection of the windings) for normal running (contactor C3 opens and C2 closes, contactor C1 remaining closed). FIGURE 5 shows the control circuit for the motor. The 3 amp fuse can be regarded as a normally closed switch (N/C), and a contact from the fused isolator as a normally open (N/O) switch. The overload current (O/L) can be regarded as a N/C switch and the start button as a N/O switch. The CENT N/C contacts are operated by a centrifugal switch on the motor and open when the motor has reached a run-up speed connected in star.
The contact positions in FIGURE 5 are the positions of the de-energised control circuit (prior to the start button being pressed).
(a) Describe briefly how you think the motor control circuit of FIGURE 5 sequence of events proceeds after pressing the start button. (The start button returns to the open position on release.)
(b) Convert the circuit to a ladder diagram using conventional plc designations for ladder input components (X000, X001, etc.) for switches, contacts, etc. and output designations Y001, Y002, Y003 for output contactor coils C1, C2, C3. Output contactor contacts in the control circuit should be designated as Y001(1-1), Y002(2-1), Y003(3-1) and Y003(3-2). Input and output designation tables may be drawn up or, alternatively, FIGURE 5 component designations can be indicated alongside the chosen plc designations. Memory relays may be used if desired.
5. Explain the operating features of an I/O data image table.
FIG. 4
FIG. 5
Part -2:
1. Design and draw a ladder diagram circuit suitable for a PLC which will fulfil the following control requirement:
A momentary push switch is to be recognised, remembered and used to switch on an output for a period of 30 seconds. After 30 seconds this output is to be switched off and must be off for 0.5 seconds before a second output switches on.
The second output remains on until a second push switch is operated to turn it off. If the second push is operated at any time then the current output must turn off and the system await the press of the first push. The rungs of the ladder diagram must contain interlock contacts which prevent both outputs being on at the same time.
2. Redesign and improve the pelican crossing ladder diagram given of FIGURE 1 of lesson PLC - 6 - 2 by adding timer rungs and counter rungs between rungs 12 and 14 (or any similar workable scheme) together with the necessary contacts inserted in the amber and green man lights of rungs 7 and 10, etc. The chart below shows the required sequence of events. Note that a section of the chart is repeated a total of 16 times. The time intervals are given below.
Time periods
|
1
|
2
|
3
|
4
|
5
|
6
|
7 ....... 35
|
36
|
37
|
Green road light
|
ON
|
ON
|
OFF
|
OFF
|
OFF
|
OFF
|
.......... OFF
|
OFF
|
ON
|
Red road light
|
OFF
|
OFF
|
OFF
|
ON
|
OFF
|
OFF
|
.......... OFF
|
OFF
|
OFF
|
Amber road light
|
OFF
|
OFF
|
ON
|
OFF
|
ON
|
OFF
|
.......... ON
|
OFF
|
OFF
|
Wait sign
|
OFF
|
ON
|
ON
|
OFF
|
OFF
|
OFF
|
.......... OFF
|
OFF
|
OFF
|
Green man
|
OFF
|
OFF
|
OFF
|
ON
|
ON
|
OFF
|
.......... ON
|
OFF
|
OFF
|
Red man
|
ON
|
ON
|
ON
|
OFF
|
OFF
|
OFF
|
.......... OFF
|
OFF
|
ON
|
,_ _, ,_ _,
first occurrence sixteenth time
Time period 1 is the 'normal' conditions.
Time period 2 is after the pedestrian presses the push button.
The change from period 2 to period 3 can only be made after at least one five second check of the road sensors.
The time interval between 3 and 4 is 4 seconds. The time interval between 4 and 5 is 10 seconds. The time interval between 5 and 6 is 0.5 seconds. The time interval between 6 and 7 is 0.5 seconds.
It is not necessary to show the whole of the traffic light ladder diagram of lesson PLC - 6 - 2, only rungs which have been modified. There must, however, be a comprehensive explanation of the operation of the modified rungs accompanying the modified ladder diagram.
3. The chart below shows a required set of step sequences with the same time interval between steps.
Provide a ladder diagram and a comprehensive explanation as a solution for this chart by using two eight-bit shift registers (SFT0 controls relays 50 to 57, SFT1 controls relays 60 to 66). The sequence is to have an initial start signal and thereafter can be free running. A reset control and timer to clock the shift registers must be provided.
STEP No.
|
OUT0
|
OUT1 OUT2 OUT3
|
OUT4
|
OUT5
|
|
RESET
|
|
all outputs off
|
|
|
RESET
|
1
|
ON
|
|
|
|
|
|
1
|
2
|
ON
|
ON
|
|
|
|
|
2
|
3
|
ON
|
ON
|
ON
|
|
|
|
3
|
4
|
|
ON
|
ON
|
ON
|
|
|
4
|
5
|
|
|
ON
|
ON
|
ON
|
|
5
|
6
|
|
|
|
ON
|
ON
|
ON
|
6
|
7
|
|
|
|
|
ON
|
ON
|
7
|
8
|
|
|
|
|
|
ON
|
8
|
9
|
|
|
|
|
ON
|
ON
|
9
|
10
|
|
|
|
ON
|
ON
|
ON
|
10
|
11
|
|
|
ON
|
ON
|
ON
|
|
11
|
12
|
|
ON
|
ON
|
ON
|
|
|
12
|
13
|
ON
|
ON
|
ON
|
|
|
|
13
|
14
|
ON
|
ON
|
|
|
|
|
14
|
15
|
ON
|
|
|
|
|
|
STEP 1 and 15
|
Return to step 2
|
|
|
|
|
|
|
|
4. (a) An A/D conversion circuit with 10 bit resolution has an input range of 0 - 5 V. A second has a 12 bit resolution and an input range of 0 - 10 V. Calculate the digital output value that will represent a 2 V input for both of the A/D converters. Convert the digital levels in both cases to hexadecimal and then to binary values.
(b) Explain briefly from what you notice about the digital output values in (a) why a digital output value of an A/D converter is rarely the exact same digital value as the analogue input value.
(c) State briefly why a PLC A/D module haveing 4 analogue input channels would probably not incorporate 4 internal A/D circuits.
(d) State briefly which of the two digital output values in (a) is the more accurate and why.
5. Explain briefly the technique of multiplexed switching of analogue signals.
6. The diagram of FIGURE 1 shows a 3 input R/2R digital to analogue converter circuit. By working back from the output (or otherwise) to find the equivalent input resistance in order to determine the input voltage, show that the output voltage values for the following digital input combinations are as shown below.
FIG. 1
7. State briefly:
(i) what is meant by a LAN
(ii) types of LAN
(iii) an application of LANs
(iv) the types of cable likely to be used in a LAN
(v) the meaning of RTU
(vi) what the current title of EIA-422 is and to what it relates
(vii) to what the protocal IEEE-488 relates.
Part -3:
This assignment assesses Outcome 3 as listed below.
Outcome 1:
- evaluate the design characteristics of typical programmable logic control devices
- describe different types of input and output devices
- evaluate the different types of communication links used in programmable logic control systems
- describe the internal architecture of a typical programmable logic device
- describe the operational characteristics of the CPU.
Outcome 2:
- evaluate the different forms of signal used in programmable logic control
- describe the resolution and relationship between analogue inputs and outputs and word length
- express numbers using different number systems
- compare the typical protocols used in signal communication
- evaluate networking methods and networking standards
- write programs using logic functions based on relay ladder logic.
Outcome 3:
- evaluate methods of programming programmable logic controllers
- evaluate the range and type of advanced functions of programmable logic controllers
- demonstrate methods of producing and storing text and documentation
- use and justify methods of testing and debugging hardware and software
- identify elements associated with the preparation of a programmable logic controller program
- produce and demonstrate a programmable logic controller program of at least 50 instructions for an engineering application.
The ladder logic files for each completed exercise should be submitted electronically via Blackboard Account when complete so that the program function can be validated.
In addition to the ladder logic files the submission should also include:
1. An allocation list of all inputs, outputs, memory relays, timers, counters, etc.
2. A description of the program functions, rung by rung.
3. A summary of how the program was developed and any difficulties encountered with each exercise.
EXERCISE 1 - ANNUNCIATOR
In industry, plant conditions are monitored and, if there are problems, it is necessary to have some way of indicating such problems. An indicator system of this type is called an Annunciator. A typical alarm system uses the following sequence to indicate a plant alarm condition to an operator.
(i) System healthy - no indication.
(ii) System in alarm - a flashing Amber light and audible alarm. FIGURE 1 shows the graphics simulation of the alarm system.
FIG. 1 Annunciator Simulation
1. If the operator presses the ACCEPT button when the plant is in alarm (ii above), the audible alarm stops and the flashing Amber light changes to permanently ‘ON'.
2. If the plant drops out of the alarm condition before the ACCEPT button is pressed, the panel will show a flashing Green light. The Audible alarm and Amber light will go ‘OFF'.
3. If the ACCEPT button was pressed when the plant is healthy as in 2 above, the flashing Green light will go ‘OFF'.
4. There should be a LAMP TEST button which, when pressed, will light all lamps and sound the audible alarm.
5. Write a program that will operate the Alarm Simulation, using the following inputs and outputs and whatever Timers and Flags are required.
IP0 = Plant alarm condition OP0 = Amber Lamp
IP1 = Operator accept button OP1 = Green Lamp
IP2 = Lamp test OP2 = Audible Alarm
6. Use the comments facility to describe the operation of the program.
EXERCISE 2 - CAR PARK
FIG. 2 Car Park Simulation
Consider the above diagram, FIGURE 2, of the car park. The object of this assignment is to write a program to operate the barriers to allow the cars in and out.
As you can see there is a box in which there are two condition lights for when the car park is Full, and when there are Spaces.
The entrance to the car park is on the left hand side. When a car drives into the car park there is a sensor that detects the car and this should cause the barrier to be opened to allow the car in.
On the right hand side is the exit. When a car leaves the car park it will activate a sensor inside the park to open the exit barrier.
Both the entry and exit barriers will need to be in the Up position long enough to allow the cars to enter or leave the car park. The inputs and outputs are listed as follows:
IP0 = Entry Sensor OP0 = Entry Barrier
IP1 = Exit Sensor OP1 = Exit Barrier
OP2 = Full Light OP3 = Spaces Light
When writing the program it is necessary to observe the following conditions. When the car park is not full the Spaces light should be ‘ON'. When the car park is full the Full light should be ‘ON'. As a car enters or leaves the car park the entry and exit barriers have to be held in the Up position long enough to allow the cars to pass under the barriers.
When the program is complete and the car park graphic is displayed in Simulation mode the program is operated by pointing at the car and clicking the mouse button. You will see directional pointers left and right so point at and click the direction you wish the car to travel. When you wish a car to leave the car park point at the one you wish to leave the park and click. You should explain the operation of the program, using the documentation facility.
EXERCISE 3 - ELEVATOR
FIGURE 3 shows the graphic simulation of the Elevator.
FIG 3 Elevator Simulation
The object of this assignment is to write a program that will drive the Elevator from one floor to the other.
The list of inputs and outputs are as follows.
IP0 External Elevator call button OP0 Elevator motor UP
IP1 Elevator on level 2 sensor OP1 Elevator motor DOWN
IP2 Elevator on level 1 sensor OP2 Elevator door motor OPEN
IP3 Internal Elevator button OP3 Elevator door motor CLOSE
IP4 Door obstruction sensor OP4 Alarm
IP5 Lift door closed sensor IP6 Lift stuck alarm button
The operation of the elevator is as follows: Assuming that the elevator is at level 1, (IP2 energised), there are two options;
1. The elevator could be called from level 2 by the external call button IP0 being pressed. The elevator doors should then close via OP3, once closed IP5 (doors closed sensor) should energise. At this point the elevator should start to move up via OP0 (elevator motor UP). Once the elevator reaches level 2, IP1 would energise and this should stop the elevator motor. After a short pause the elevator doors should open via OP2.
2. The elevator could also be operated from level 1 via the internal button IP3. The elevator doors would then close (OP3) energising IP5 (doors closed sensor). The elevator should then move up to level 2 via OP0. Once level 2 sensor IP1 energises, the elevator doors can then open via OP2.
Note: When the elevator is on level 2 it will be necessary to drive the elevator down to level 1 using OP1 (elevator motor DOWN).
Other facilities:
(a) Alarm: Should the elevator get stuck between floors or the
doors not open, then by pressing IP6 the alarm OP4 should operate.
(b) Door Obstruction: If the doors are obstructed the elevator motors OP0
and OP1 should be disabled. You can test this by clicking on the box and obstructing the doors.
When writing the program use the inputs and outputs as listed, use any flags, timers, and counters as required. As usual use the comments facilities to document your program.
EXERCISE 4 - DRINKS MACHINE
FIGURE 4 shows the graphics simulation of the drinks machine.
FIG. 4 Drinks Machine Simulation The list of inputs and outputs is as follows:
The operation of the Soft Drinks Machine is as follows;
When a coin is clicked on with the mouse it is placed into the slot, it then operates the coin sensor IP0. This should operate OP0 (coin hold solenoid), which will hold the coin in place. At this point either a drink is selected or the coin rejected.
The rejection of a coin is by operating IP5, which should reset OP0 allowing the coin to fall into the rejection box. If a coin is rejected, pointing the mouse at the coin and clicking resets the machine.
If a drink is selected by the operation of one of the drink select buttons, OP1 (coin accept solenoid) should operate. This allows the coin to fall into the Kept box. Once the coin has dropped into the box, the solenoid corresponding to the selected drink should operate, allowing the drink to be dispensed.
Once the selected drink has been dispensed, clicking the coin will reset the machine.
Important Notes: When writing the program you must ensure that:
(a) The coin cannot be rejected once a drink has been selected.
(b) Selecting a drink disables all of the other drink buttons.
As usual, use the listed inputs and outputs and any flags, timers, and counters you require to complete the assignment. Use the documentation facilities to describe the program function.
EXERCISE 5 - PACKING LINE
The packing line simulation is shown in FIGURE 5.
FIG. 5 Packing Line Simulation
This exercise involves programming the simulator of FIGURE 5.The packing line carries boxes of different sizes that need to be separated at the end of the first conveyor. Which direction the boxes travel at the end of the first conveyor should be decided by using the input sensors IP1 and IP2. If the box is a short one, the inputs will only be energised one at a time. If the box is a long one then, for a short period, both inputs will energise at the same time.
When the box reaches the end of the first conveyor, which is driven by OP0, it will come to rest on the circular plate and will energise the sensor IP3 (the first conveyor will also stop). The plate will then turn either to the left or the right depending on the length of the box. OP2 turns the plate to the right; OP1 turns the plate to the left.
Once the plate has turned, the box will be pushed on to the next conveyor by either piston OP4 or OP3. Output OP6 drives the left-hand conveyor and output OP5 drives the vertical conveyor. Inputs IP4 and IP5 are sensors which detect the boxes on the conveyors as they are transported to the correct loading areas depending on their length.Once the boxes pass these sensors there should be a short delay and the respective conveyor should stop.
Write a program to carry out the previously described operation and, as with the previous assignments, use the documentation facilities. When the program is complete, test its operation using the simulation package. To use the graphic simulation click on a box which, will place the selected box on to the first conveyor then operate the start switch IP0.
The following is a list of the inputs and outputs, in addition to this list use any of the Flags, Timers, and Counters that you require in your program.
IP0 Start button OP0 Loading conveyor
IP1/2 Box length sensors OP1 Turns direction plate to the left
IP3 Box on the direction plate OP2 Turns direction plate to the
sensor right
IP4 Box on the vertical sensor OP3 Push the box on to the vertical conveyor
IP5 Box on the left conveyor OP4 Push the box on to the left
sensor conveyor
OP5 Vertical conveyor OP6 Left hand conveyor
EXERCISE 6 - BOTTLING PLANT
FIGURE 6 shows a graphic of the Bottling Plant Simulation. It represents the area where the bottles are filled and then sent on to the packing area. The object of this assignment is to write a program that will control the bottling plant simulation. The program should be fully documented.
FIG. 6 Bottling Plant Simulation
The Inputs and Outputs are listed below:
IP0 Bottle stop sensor OP0 Conveyor 1
IP1 level sensor OP1 Stop bottle piston
IP2 Sol 4 limit switch OP2 Cap plunger piston
IP3 Bottle clear OP3 Bottle filler piston
IP4 Bottle in winder sensor OP4 Conveyor 2
IP5 Counter sensor OP5 Cap winder piston
IP6 Stacker piston limit switch OP6 Stacker piston
OP7 Stacker to conveyor 3
A little thought must first be given to understanding the bottling process. With reference to FIGURE 6, conveyor 1 runs continuously and is fed one bottle at a time. Each bottle travels along the conveyor and is guided to the position where it is filled and capped. A sensor, IP0, detects when the bottle reaches the position and a piston controlled by OP1 is activated and stops the bottle. With the bottle in this position, the filler nozzle piston is activated by OP3 which pushes the nozzle into the neck of the bottle. As it goes into the bottle, a valve automatically opens allowing the liquid to be released into the bottle. This is simulated in the ‘Filling Station' section.
When the liquid in the bottle activates the level sensor IP1, OP3 de-activates, lifting the nozzle out of the bottle. A few seconds after the nozzle has cleared the bottle, the cap plunger piston OP2 activates, pushing a cap on to the bottle. At the end of the piston travel is a limit switch IP2 which operates as the cap is placed on the bottle. This switch de-activates OP2 retracting the piston and leaving the cap on the bottle. It also de-activates OP1 releasing the bottle stop piston. IP3 will see the bottle as it leaves the filling area.
At this point the cap just rests on the filled bottle and must still be screwed tight. To achieve this, the bottle passes onto conveyor 2 where it is guided into the ‘cap winder' area. As it enters this area, a sensor (IP4) detects its presence and this activates the cap winder piston via OP5. The operation of this piston closes the guide just enough to put pressure on one side of the cap and, as the bottle travels down the conveyor; this causes the cap to rotate and tighten on the bottle.
When the bottle reaches the end of conveyor 2 it activates the Counter Sensor IP5. This sensor has three functions:
1. It deactivates the cap winder piston OP5.
2. It counts the number of bottles onto the Stacker.
3. When three bottles have passed onto the stacker it operates the stacker piston via OP6 and this pushes the three bottles clear to allow the next three bottles onto the stacker.
When 9 bottles are on the stacker it will operate the piston OP7, which lowers the stacker platform to conveyor 3 as shown in the stacker section of the FIGURE 6. At this point, the 9 bottles are pushed onto conveyor 3 but the operation of this, and conveyor 2, is taken care of automatically so it is not the concern of your program.
When the stacker piston extends it operates a limit switch at the end of its travel de-activating the piston.
EXERCISE 7 - INDUSTRIAL CONTROL SIMULATOR
FIG. 7 Bytronic Industrial Control Trainer (ICT3)
The Industrial Control Trainer is a mini-production line trainer. The system has been designed to realistically represent a component sorting, assembly and inspection process that can be controlled from virtually any Programmable Logic Controller with relay outputs or a PC with a suitable interface card. In principle, the unit is designed to sort an aluminium ‘peg' from a plastic ‘ring', then assemble these two components and check for correct assembly. The components are initially randomly placed on the chain conveyor and are lifted to a higher level. When the higher level is reached, the plastic components are detected by an infra-red emitter/detector and ejected by a solenoid down an assembly chute. The aluminium pegs, meanwhile, continue on the conveyor and are finally deflected down the feeder chute. From the feeder chute the aluminium components are automatically fed on to the belt conveyor.
An infra red emitter detector is used to determine whether or not the assembly ‘hopper' is empty. If it is, a rotary solenoid is used to dispense a ring from the assembly chute into the hopper. The hopper is positioned just above the belt conveyor and, when the aluminium peg passes, the peg engages with the hole in the ring and the two are thus assembled. Inductive, capacitive, infra-red and fibre-optic industrial sensors positioned along the belt conveyor are used to check for correct assembly. Components that have not been assembled are ejected by a solenoid into a ‘scrap' or ‘recycle' bin while correctly assembled components pass into a finished parts tray.
FIG. 8 Industrial Controller Simulation
The Ladsim ICT3 simulation shows the Industrial Controller from above and performs as a slightly simplified representation of it. Rings and pegs are placed onto the chain conveyor from the green source hopper by clicking upon them.
Inputs
Label
|
Name
|
Non-detection status
|
IP0
|
Metal Peg Detect
|
Low
|
IP1
|
Sort Area
|
Low
|
IP2
|
Hopper Full
|
Low
|
IP3
|
Ring Assembled
|
High
|
IP4
|
Component Detect
|
High
|
IP5
|
Reject Area
|
Low
|
IP6
|
Start
|
Low
|
IP7
|
Stop
|
High
|
IP8
|
Belt Peg Detect
|
Low
|
Outputs
Label Name
OP0 Chain Motor (upper conveyor motor) OP1 Sort Solenoid
OP2 Rotary Solenoid (allow rings into hopper) OP3 Reject Area
OP4 Belt Motor (lower conveyor motor).
When OP0 is on, the rings and pegs will move along the chain conveyor. IP1 detects the presence of any item in the sort area. Simultaneously IP0 detects the presence of a peg. Activating OP1 will push an item in the sort area down the ring chute. Pushing a peg into the chute will jam the system and cause an error. The simulation will then stop and you will be informed of the error. Rings that are not sorted from the chain conveyor continue along and are fed down the end chute onto the belt conveyor where they continue along the conveyor and should eventually be rejected. Rings that are sorted into the ring chute are held in place until OP2, the rotary solenoid, is activated. This loads a single ring into the hopper, holding any others waiting in the queue. When a ring is indexed into the hopper, IP2 activates to indicate the hopper is now full and the ring is lined up to load onto any peg passing beneath. If the rotary solenoid, OP2, is activated with the hopper already full, the hopper will jam and the simulation will halt. The ring chute can hold five rings in addition to one in the ring hopper; an attempt to push another into the chute will produce a warning that this latest ring will bounce off the waiting stack and continue along the chain conveyor.
OP4 activates the belt conveyor. Pegs on the belt conveyor automatically line up with the ring hopper. The inductive and capacitive sensors IP8 and IP3 simultaneously detect the properties of an item. IP8 detects metal and so is activated by either single pegs or assembled pegs.
IP3 detects the presence of an object adjacent to the sensor and is positioned in such a way that it only detects an assembled ring. Further down the belt, the through-beam sensor IP4 senses any passing item. At the end of the belt IP5 detects any item in the reject area. Activation of OP3 will push any item in the reject area into the red reject bin. A tally of assemblies that have entered the "accept area" and lone rings and pegs pushed into the reject bin should be kept. A complete control program should do the following:
- Use the Start and Stop buttons IP6 and IP7 to activate and deactivate both the chain conveyor OP0, and the belt conveyor OP4.
- Use the Metal Peg Detect IP0 and Sort Area IP1 sensors at the sorting area to determine the identity of the item and by activating the Sort Solenoid OP1, sort the rings into the ring chute. Pegs should be allowed to pass, enabling them to continue down onto the belt conveyor.
- Use a counter to record the number of rings in the chute: when full (5 rings in queue), no further rings should be added.
- Activate the Rotary Solenoid OP2 to dispense rings into the assembly hopper when the Hopper Full sensor IP2 indicates that it is empty.
- Use the Belt Peg Detect sensor IP8 and the Ring Assembled sensor IP3 to determine whether the component is a correctly assembled part.
- Use the Component Detect sensor IP4 as an index to allow for multiple components on the belt conveyor.
- Use the Reject Area sensor IP5 to detect when a part is at the reject area and determine from the data captured previously whether the component needs to be accepted or rejected. Use the Reject Solenoid OP3 to reject bad components off the conveyor.